Activation Energy Calculator

Find activation energy from rate constants at two temperatures.

Activation energy (kJ/mol) 91.89

Formula: Ea = R · ln(k₂/k₁) ÷ (1/T₁ − 1/T₂)

Step-by-step with your numbers:
1. Values used:
2. Rate constant k₁ = 0.001
3. Temperature T₁ = 300 K
4. Rate constant k₂ = 0.01
5. Temperature T₂ = 320 K
6.
7. Activation energy = 91.89kJ/mol
Did we solve your problem today?

Find a reaction's activation energy from rates measured at two temperatures.

The math behind it

From the Arrhenius equation: Ea = R × ln(k₂/k₁) ÷ (1/T₁ − 1/T₂).

Worked example

k doubles ×10 from 300→320 K → ~92 kJ/mol.

FAQ

Higher Ea?

Means the rate is more temperature-sensitive.