Blackbody Radiation Calculator

Find radiated power per area from temperature (Stefan–Boltzmann).

Radiated power per area (W/m²) 459.3

Peak wavelength (nm) 9,659.24

Formula: j = σ·T⁴ ; λ_peak = b ÷ T

Step-by-step with your numbers:

1. Values used:

2. Temperature = 300 K

4. Radiated power per area = 459.3W/m²

5. Peak wavelength = 9,659.24nm

Did we solve your problem today?

A hot object radiates energy that grows steeply with temperature.

The math behind it

Stefan–Boltzmann: j = σ·T⁴. Wien's law gives the peak wavelength λ = b/T.

300 K → about 459 W/m², peaking near 9659 nm (infrared).

Why does T⁴ matter?

Doubling temperature multiplies radiated power 16-fold.