Bridge Rectifier Calculator

Find the DC output of a full-wave bridge rectifier.

Peak voltage (V) 15.571

Average DC output (V) 9.913

Formula: V_peak = V_rms·√2 − 2·V_diode; V_dc = 2·V_peak/π

Step-by-step with your numbers:

1. Values used:

2. Input RMS voltage = 12 V

3. Diode drop = 0.7 V

5. Peak voltage = 15.571V

6. Average DC output = 9.913V

Did we solve your problem today?

A bridge rectifier converts AC to pulsating DC using four diodes.

The math behind it

Peak ≈ V_rms·√2 minus two diode drops; the average DC of a full-wave output is 2·V_peak/π.

12 V RMS, 0.7 V diodes → about 15.6 V peak, 9.9 V average.

Why two diode drops?

Current always passes through two of the four bridge diodes in series.